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0=360x-2x^2
We move all terms to the left:
0-(360x-2x^2)=0
We add all the numbers together, and all the variables
-(360x-2x^2)=0
We get rid of parentheses
2x^2-360x=0
a = 2; b = -360; c = 0;
Δ = b2-4ac
Δ = -3602-4·2·0
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{129600}=360$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-360}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+360}{2*2}=\frac{720}{4} =180 $
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